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4. STRUCTURAL DESIGN OF LVL STRUCTURES

It is recommended to have the tapered edge on the com-

pressive side, especially for LVL-P, since the tension perpendic-

ular to grain strength

f

t,90,edge,k

is low, which can lead to cracks

and brittle failure. LVL-C may be used for special shapes, also

when the tapered edge is on the tensile side, as its

f

t,90,edge,k

is

higher due to the cross veneers and it behaves more ductile.

Figure 4.21 shows the

k

m,α

factors as a function of the angle

α

.

For high pitched roof beams (α ≥ ~10°) the maximum

shear stress

τ

v,max,d

and tension perpendicular to the grain

σ

90,max,d

shall be calculated at the point of the maximum bend-

ing moment stress with the equations:

τ_(v,max,d)=σ_(m,0,max,d)∙tanα

(4.55)

30

σ_(90,max,d)=σ_(m,0,max,d)∙tan^2 α

(4.56)

30

Figure 4.23.

Stress distributions in single and double-tapered beams. When the angle between loading and the grain is large (

α

≥ 10°), shear

stress at the point of maximum bending moment stress may become more critical than the shear stress at the support

30

.

Figure 4.24.

Stresses at the tapered edge of a beam: bending stress

σ

m,α

at the direction of the edge, bending stress at the grain direction

σ

0

,

shear stress

τ

=

σ

0

∙tanα and stress perpendicular to the grain

σ

90

=

σ

0

∙tan

2

α

30

.

For double-tapered, curved and pitched camber beams de-

sign instruction are given in Eurocode 5 clause 6.4.3. Addition-

al information to the clause:

• Factor

k

r

is 1,0 for LVL in the edgewise direction, as the shape

of the beam is cut directly from a panel and no reduction due

to bending of the laminates during production is needed.

k

m,α

is not used together with the equations for checking the

stresses at the apex point.

• It is not necessary to take kl into consideration in the resist-

ance against lateral torsional buckling of the beam (4.38).

v,max,d

=

m,0,max,d

∙ tan

(4.55)

30

90,max,d

=

m,0,max,d

∙ tan

2

(4.56)

30

v,max,d

=

m,0,max,d

∙ tan

(4.55)

30

90,max,d

=

m,0,max,d

∙ tan

2

(4.56)

30

LVL Handbook Europe

133