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9. CALCULATION EXAMPLES OF LVL STRUCTURES

Loading combinations

Snow load at roof level

q

k

= μ

1

C

e

s

k

. Form factor μ

1

=0,8, when roof angle is less than 30° and in normal

conditions

C

e

= 1,0 →

q

k

= 0,8 ∙ 1,0 ∙ 2,75 N/m

2

= 2,2 kN/m

2

.

The most critical ultimate limit state (ULS) load combination:

E_(d,ULS )= γ_G∙g_k+ γ_Q∙q_k

(4.1)

E_(d,ULS )= 1,15∙(5m∙1,0 kN/m^2 )+1,5∙5m∙2,2 kN/m^2=22,3 kN/m

Note: Safety factors γ

G

and γ

Q

are according to Finnish National annex of Eurocode 0.

The most critical serviceability limit state (SLS) load combination:

E_(d,SLS) = γ_G∙g_k + γ_Q∙q_k

(4.1)

E_(d,SLS) = 1,0∙(5m∙1,0 kN/m^2+1,0∙5m∙2,2kN/m^2=16,0 kN/m

ULS design

Bending moment resistance

M_d= E_(d,ULS)∙s∙L^2/8 = 22,3kN/m∙〖(2,3m)〗^2/8 = 14,7 kNm

σ_(m,d)=M_d/W=(14,7 kNm)/(6,75〖∙10〗^6 mm^3 )=21,8 N/mm^2

f_(m,0,edge,d)=k_mod/γ_M ∙k_h∙f_(m,0,edge,k)=0,8/1,2∙1,00∙44 N/mm^2 =29,3 N/mm^2

σ_(m,d)≤f_(m,0,edge,d) →OK

Lateral torsional buckling

The lintel beam is laterally supported to wall studs in 600mm spacing and the load is applied via them.

Therefore the effective length is

L

ef

= 600mm (See table 4.9).

σ_(m,crit)=M_(y,crit)/W_y =(π√(E_0,05 I_z G_0,05 I_tor ))/(l_ef W_y )

(4.42)

σ_(m,crit)= (π√(10600 N/mm^2∙2,28∙〖10〗^6 mm^4∙400N/mm^2 ∙8,20∙〖10〗^6∙

〗^5 mm^3 )

σ_(m,crit)=72,2 N/〖mm〗^2

λ_rel=√(f_(m,k)/σ_(m,crit) )=√((44 N/mm^2)/(72,2N/mm^2 ))= 0,78

(4.41)

when 0,75<λ_(rel,m)≤1,4 ,k_crit=1,56-0,75∙λ_(rel,m)=1,56-0,75∙0,78=0,97

d,ULS

=

G

k

+

Q

k

(4.1)

d,ULS

= 1,15 ∙ �5m ∙ 1,0 kNm

2

� + 1,5 ∙ 5m ∙ 2,2 kN/m

2

= 22,3 kN/m

d,SLS

=

G

k

+

Q

k

(4.1)

d,SLS

= 1,0 ∙ (5m ∙ 1,0 kN/m

2

+ 1,0 ∙ 5m ∙ 2,2kN/m

2

= 16,0 kN/m

d

=

d,ULS

∙ ∙

2

/8 = 22,3kN/m ∙ (2,3m)

2

/8 = 14,7 kNm

m,d

= = 14,7 kNm 6,75 ∙ 10

6

mm

3

= 21,8 N/mm

2

m,0,edge,d

=

mod M

h

m,0,edge,k

= 0,8 1,2 ∙ 1,00 ∙ 44 Nmm

2

= 29,3 N/mm

2

m,d

m,0,edge,d

→ OK

m,crit

=

y,crit y

=

0,05 z 0,05 tor

ef y

(4.42)

m,crit

= π�10600 N/mm

2

∙ 2,28 ∙ 10

6

mm

4

∙ 400Nmm

2

∙ 8,20 ∙ 10

6

∙ mm

4

600mm ∙ 6,75 ∙ 10

5

mm

3

m,crit

= 72,2 /

2

= �

m,k m,crit

= �

44 N/mm

2

72,2N/mm

2

= 0,78

(4.41)

when 0,75 <

rel,m

≤ 1,4 ,

crit

= 1,56 − 0,75 ∙

rel,m

= 1,56 − 0,75 ∙ 0,78 = 0,97

crit

m,d

= 0,97 ∙ 29,3 N/mm

2

= 28,6 N/mm

2

m,d

crit

m,d

d

=

d,ULS

∙ ∙ /2 = 22,3kN/m ∙ 2,3m/2 = 25,6 kN

d,ULS

=

G

k

+

Q

k

(4.1)

d,ULS

= 1,15 ∙ �5m ∙ 1,0 kNm

2

� + 1,5 ∙ 5m ∙ 2,2 kN/m

2

= 22,3 kN/m

d,SLS

=

G

k

+

Q

k

(4.1)

d,SLS

= 1,0 ∙ (5m ∙ 1,0 kN/m

2

+ 1,0 ∙ 5m ∙ 2,2kN/m

2

= 16,0 kN/m

d

=

d,ULS

∙ ∙

2

/8 = 22,3kN/m ∙ (2,3m)

2

/8 = 14,7 kNm

m,d

= = 14,7 kN 6,75 ∙ 10

6

mm

3

= 21,8 N/mm

2

m,0,edge,d

=

mod M

h

m,0,edge,k

= 0,8 1,2 ∙ 1,00 ∙ 44 Nmm

2

= 29,3 N/mm

2

m,d

m,0,edge,d

→ OK

m,crit

=

y,crit y

=

0,05 z 0,05 tor

ef y

(4.42)

m,crit

= π�10600 N/mm

2

∙ 2,28 ∙ 10

6

mm

4

∙ 400Nmm

2

∙ 8,20 ∙ 10

6

∙ mm

4

600mm ∙ 6,75 ∙ 10

5

mm

3

m,crit

= 72,2 /

2

= �

m,k m,crit

= �

44 N/mm

2

72,2N/mm

2

= 0,78

(4.41)

when 0,75 <

rel,m

≤ 1,4 ,

crit

= 1,56 − 0,75 ∙

rel,m

= 1,56 − 0,75 ∙ 0,78 = 0,97

crit

m,d

= 0,97 ∙ 29,3 N/mm

2

= 28,6 N/mm

2

m,d

crit

m,d

d

=

d,ULS

∙ ∙ /2 = 22,3kN/m ∙ 2,3m/2 = 25,6 kN

d,UL

=

G

k

+

Q

k

(4.1)

d,ULS

= 1,15 ∙ �5m ∙ 1,0 kNm

2

� + 1,5 ∙ 5m ∙ 2,2 kN/m

2

= 22,3 kN/m

d,SLS

=

G

k

+

Q

k

(4.1)

d,SLS

= 1,0 ∙ (5m ∙ 1,0 kN/m

2

+ 1,0 ∙ 5m ∙ 2,2kN/m

2

= 16,0 kN/m

d

=

d,ULS

∙ ∙

2

/8 = 22,3kN/m ∙ (2,3m)

2

/8 = 14,7 k

m,d

= = 14,7 kNm 6,75 ∙ 10

6

mm

3

= 21,8 N/mm

2

m,0,edge,d

=

mod M

h

m,0,edge,k

= 0,8 1,2 ∙ 1,00 ∙ 44 Nmm

2

= 29,3 N/mm

2

m,d

m,0,edge,d

→ OK

m,crit

=

y,crit y

=

0,05 z 0,05 tor

ef y

(4.42)

m,crit

= π�10600 N/mm

2

∙ 2,28 ∙ 10

6

mm

4

∙ 400Nmm

2

∙ 8,20 ∙ 10

6

∙ mm

4

600mm ∙ 6,75 ∙ 10

5

mm

3

m,crit

= 72,2 /

2

= �

m,k m,crit

= �

44 N/mm

2

72,2N/mm

2

= 0,78

(4.41)

when 0,75 <

rel,m

≤ 1,4 ,

crit

= 1,56 − 0,75 ∙

rel,m

= 1,56 − 0,75 ∙ 0,78 = 0,97

crit

m,d

= 0,97 ∙ 29,3 N/mm

2

= 28,6 N/mm

2

m,d

crit

m,d

d

=

d,ULS

∙ ∙ /2 = 22,3kN/m ∙ 2,3m/2 = 25,6 kN

d,ULS

=

G

+

( . )

,

S

= , 5 ∙ 5 ∙ , m

2

, ∙

∙ ,

2

,

,S S

+

( . )

,S S

, ∙ ( ∙ ,

2

, ∙

∙ ,

2

,

d,U S

∙ ∙

2

8

2,

(2,

)

2

/

4,

m,

= 1 , kNm ,75 ∙ 10

6 3

, /

2

m,0,e ge,d

,0,e ge,

0,8 1,2 ∙ ,

Nmm

2

, /

2

,

,0,e ge,

,crit

=

y,crit y

=

0,05 z 0,05 tor

ef y

(4.42)

,crit

6

m

2

∙ ,2 ∙ 0

6 4

∙ 4 0m

2

∙ ,

6

4

∙ ,

5

m

3

,crit

2,2

2

m,k ,crit

44 /

2

72,2 /

2

,

( . )

, 5

rel,

≤ , ,

crit

= ,

,

rel,

,

,

∙ ,

,

crit

,

= , 7 ∙

,

2

,

2

,

crit

,

,

S

∙ ∙

,

m ∙ ,

,

LVL Handbook Europe

185