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9. CALCULATION EXAMPLES OF LVL STRUCTURES

ULS design

Bending moment resistance

M_d = E_(d,ULS)∙s∙L^2/8 = 4,03kN/m^2∙0,4m∙〖(4,5m)〗^2/8 = 4,

σ_(m,d)=M_d/W=(4,1 kNm)/(4,32〖∙10〗^5 mm^3 )=9,5 N/mm^2

f_(m,0,edge,d)=k_mod/γ_M ∙k_h∙f_(m,0,edge,k)

(4.3)

f_(m,0,edge,d)=0,8/1,2∙1,034∙44 N/mm^2 =30,3 N/mm^2

σ_(m,d)≤f_(m,0,edge,d) →OK

Lateral torsional buckling is prevented by the fixing of the decking.

Shear resistance

V_d = E_(d,ULS)∙s∙L/2 = 4,03kN/m^2∙0,4m∙4,5m/2 = 3,6 kN

τ_(v,d)=〖3∙V〗_d/(2∙A)=(3∙3,6 kN)/(2 ∙10 800mm^2 )=0,5 N/mm^2

f_(v,0,edge,d)=k_mod/γ_M ∙f_(v,0,edge,k)=0,8/1,2∙4,2 N/mm^2 =2,8 N/mm^2

τ_(m,d)≤f_(v,0,edge,d) →OK

Compression perpendicular to the grain

F_(c,90,d) = V_d = 3,6 kN

σ_(c,90,d)=F_(c,90,d)/A_ef =F_(c,90,d)/(b∙(l_s

(4.14)

σ_(c,90,d)=3,6kN/(45 mm∙(45 mm+15mm

k_(c,90)∙f_(c,90,edge,d)=k_(c,90)∙k_mod/γ_M ∙

(4.13)

k_(c,90)∙f_(c,90,edge,d)=1,0∙0,8/1,2∙6 N/mm^2=4

(

k

c,90

Table 4.7)

σ_(c,90,d)≤k_(c,90)∙f_(m,0,edge,d) →OK

SLS design

Instantaneous deflection

w_inst = w_(inst,g) + w_(inst,q)

w_(inst,g)=(5〖∙g〗_(d,SLS)∙

(4.74)

d,SLS

G 1,k 2,k

G k

(4.1)

d,SLS

= 1,0 ∙ (0,6 kN/m

2

+ 0,3 kN/m

2

) + 1,0 ∙ 2,0 kN/m

2

d,SLS

= 2,9 kN/m

2

d

=

d,ULS

∙ ∙

2

/8 = 4,03kN/m

2

∙ 0,4 ∙ (4,5m)

2

/8 = 4,1 kNm

m,d

=

d

= 4,1 kNm 4,32 ∙ 10

5

mm

3

= 9,5 N/mm

2

m,0,edge,d

=

mod M

h

m,0,edge,k

(4.3)

m,0,edge,d

= 0,8 1,2 ∙ 1,034 ∙ 44 Nmm

2

= 30,3 N/mm

2

m,d

m,0,edge,d

→ OK

d

=

d,ULS

∙ ∙ /2 = 4,03kN/m

2

∙ 0,4m ∙ 4,5m/2 = 3,6 kN

d,SLS

=

G

∙ (

1,k

+

2,k

) +

G

k

(4.1)

d,SLS

= 1,0 ∙ (0,6 kN/m

2

+ 0,3 kN/m

2

) + 1,0 ∙ 2,0 kN/m

2

d,SLS

= 2,9 kN/m

2

d

=

d,ULS

∙ ∙

2

/8 = 4,03kN/m

2

∙ 0,4m ∙ (4,5m)

2

/8 = 4,1 kNm

m,d

=

d

= 4,1 kNm 4,32 ∙ 10

5

mm

3

= 9,5 N/mm

2

m,0,edge,d

=

mod M

h

m,0,edge,k

(4.3)

m,0,edge,d

= 0,8 1,2 ∙ 1,034 ∙ 44 Nmm

2

= 30,3 N/mm

2

m,d

m,0,edge,d

→ OK

d

=

d,ULS

∙ ∙ /2 = 4,03kN/m

2

∙ 0,4m ∙ 4,5m/2 = 3,6 kN

v,d

= 3 ∙

d

2 ∙

= 3 ∙ 3,6 kN

2 ∙ 10 800mm

2

= 0,5 N/mm

2

v,0,edge,d

=

mod M

v,0,edge,k

= 0,8 1,2 ∙ 4,2 Nmm

2

= 2,8 N/mm

2

m,d

v,0,edge,d

→ OK

c,90,d

=

d

= 3,6 kN

c,90,d

=

c,90,d ef

=

c,90,d

∙�

support

+15 mm�

(4.14)

c,90,d

=

3,6kN

45 mm ∙ (45 mm + 15mm) = 1,35 N/mm

2

c,90

c,90,edge,d

=

c,90

mod M

c,90,edge,k

(4.13)

c,90

c,90,edge,d

= 1,0 ∙

0,8 1,2

∙ 6 N/mm

2

= 4N/mm

2

(

k

c,90

Table 4.7)

c,90,d

c,90

m,0,edge,d

→ OK

inst

=

inst,g

+

inst,q

inst,g

=

5∙

d,SLS

∙ ∙

4

384∙

mean

+

6 5

d,SLS

∙ ∙

2

8∙

mean

(4.74)

inst,g

= 2,69 mm + 0,17 mm = 2,86 mm

inst,q

= 5 ∙

d,SLS

∙ ∙

4

384 ∙

mean

∙ + 6/5 ∙

d,SLS

∙ ∙

2

8 ∙

mean

= 5,97 mm + 0,38 mm = 6,35 mm

d

2 ∙

k 1 0

0,5 N/mm

0

d

0 e k

,

2

d

0 e ,d

O

=

d e

c

t

=

,9

9 e k

c,9

9 e d

0,8 1,2

N

g

3 4

6 5

m

6

∙ 8

+

d S S

= 5,97 mm + 0,38 mm = 6,35 mm

v,d

= 3 ∙

d

2 ∙

= 3 ∙ 3,6 kN

2 ∙ 10 800mm

2

= 0,5 N/mm

2

v,0,edge,d

=

mod M

v,0,edge,k

= 0,8 1,2 ∙ 4,2 Nmm

2

= 2,8 N/mm

2

m,d

v,0,edge,d

→ OK

c,90,d

=

d

= 3,6 kN

c,90,d

=

c,90,d ef

=

c,90,d

∙�

support

+15 mm�

(4.14)

c,90,d

=

3,6kN

45 mm ∙ (45 mm + 15mm) = 1,35 N/mm

2

c,90

c,90,edge,d

=

c,90

mod M

c,90,edge,k

(4.13)

c,90

c,90,edge,d

= 1,0 ∙

0,8 1,2

∙ 6 N/mm

2

= 4N/mm

2

(

k

c,90

Table 4.7)

c,90,d

c,90

m,0,edge,d

→ OK

inst

=

inst,g

+

inst,q

inst,g

=

5∙

d,SLS

∙ ∙

4

384∙

mean

+

6 5

d,SLS

∙ ∙

2

8∙

mean

(4.74)

inst,g

= 2,69 mm + 0,17 mm = 2,86 mm

inst,q

= 5 ∙

d,SLS

∙ ∙

4

384 ∙

mean

∙ + 6/5 ∙

d,SLS

∙ ∙

2

8 ∙

mean

= 5,97 mm + 0,38 mm = 6,35 mm

216 (255)

0,edge,d

= 0,8 1,2 ∙ 1,034 ∙ 44 Nmm

2

= 30,3 N/mm

2

m,d

m,0,edge,d

→ OK

Lateral torsional buckling is prevented by the fixing of the decking.

hear resistance

d

d,ULS

∙ ∙ /2 = 4,03kN/m

2

∙ 0,4m ∙ 4,5m/2 = 3,6 kN

v,d

= 3 ∙

d

2 ∙

= 3 ∙ 3,6 kN

2 10 800mm

2

= 0,5 N/mm

2

v,0,edge,d

=

mod M

v,0,edge,k

= 0,8 1,2 ∙ 4,2 Nmm

2

= 2,8 N/mm

2

m,d

v,0,edge,d

→ OK

ompression perpen icular to the grain

,

,d

=

d

= 3,6 kN

c,90,d

=

c,90,d ef

=

c,90,d

∙�

support

+15 mm�

(4.14)

c,90,d

=

3,6kN

45 mm ∙ (45 mm + 15mm) = 1,35 N/mm

2

c,90

c,90,edge,d c,90

mod M

c,90,edge,k

(4.13)

,

c,90,edge,d

= 1,0 ∙

0,8 1,2

∙ 6 N/mm

2

= 4N/mm

2

(

k

c,90

Table 4.7)

c,90,d

c,90

m,0,edge,d

→ OK

LS design

nstantaneous deflection

inst

=

inst,g

+

inst,q

i ,g

5 ∙

d,SLS

∙ ∙

4

384 ∙

mean

∙ + 6/5 ∙

d,SLS

∙ ∙

2

8 ∙

mean

= 2,69 mm + 0,17 mm = 2,86 mm

(4.74)

d,SLS

4

d,SLS

2

180

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