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V_(d,(x=323mm))=0,4 m∙4,03 kN/m^2 ∙(1-(0,3 m+0,045 m/2)/(4,5 m))=3,13 kN

M_(d,(x=323mm))=(0,4 m∙4,03 kN/m^2 ∙(0,3 m+0,045 m/2))/2∙(4,5 m-(0,3 m+(0,045 m)/2))

M_(d,(x=323mm))=1,1 kNm

F_(t,90,d)=(3,13 kN∙0,06 m)/(4∙0,24 m)∙[3-((0,06 m)/0,24m)^2 ]+0,008∙(1,1 kNm)/(0,09 m)=0,57 kN+0,10

kN=0,67 kN

σ_(t,90,d)=F_(t,90,d)/(0,5∙l_(t,90)∙b∙k_(t,90) )=(0,67 kN)/(0,5∙0,15 m∙0,045 m∙1,0)=0,20 N/mm^2 ≤f_

(t,90,d)→OK

The verification of shear stress concentration at the hole edge shall fulfil the condition:

τ_d=k_τ∙(1,5∙V_d)/(b∙(h-h_d ) )≤f_(v,d)

(4.62)

Where

k_τ=1,85∙(1+a/h)∙(h_d/h)^0,2=1,85∙(1+(0,14 m)/(0,24 m))∙((0,06 m)/(0,24 m)

(4.63)

τ_d=k_τ∙(1,5∙V_d)/(b∙(h-h_d ) )=2,22∙(1,5∙3,13 kN)/(45 mm∙(240 mm-60 mm) )=

f_(v,0,edge,d)=k_mod/γ_M ∙f_(v,0,edge,k)=0,8/1,2∙4,5 N/mm^2 =3,0 N/mm^2

τ_d≤f_(v,0,edge,d)→OK

Bending stress at the location of a rectangular hole is verified by the equations:

(M_d/W_n +M_(o,d)/W_o )/f_(m,d) ≤1 and (M_d/W_n +M_(u,

(4.64 and 4.65)

Where

W_n=(b∙(h^2-h_d^2 ))/6=(45 mm∙((240 mm)^2 〖-(60 mm)〗^2 ))/6=4,0

(4.66)

M_(o,d)=A_o/(A_u+A_o )∙V_d∙a/2=(b∙h_ro)/(b∙h_ro+b∙h_ru )∙V_d∙a/2

(4.67)

M_(o,d)=(45 mm∙90 mm)/(45 mm∙90 mm+45 mm∙90 mm)∙3,13 kN∙(140 mm

W_o=(b∙h_ro^2)/6=(45 mm∙(90 mm)^2)/6=60750 mm^3

(4.69)

f_(m,0,d)=k_mod/γ_M ∙k_h∙f_(m,0,k)=0,8/1,2∙1,03∙32 N/mm^2 =22,1 N/mm^2

(M_d/W_n +M_(o,d)/W_o )/f_(m,d) =((1,1 kNm)/(4,05∙〖10〗^5 mm^3 )+(0,

(22,1N/mm^2 )=(4,5N/mm^2)/(22,1N/mm^2 )=0,20≤1→OK

Since the hole is at the centre line of the cross section, only one of the equations (4.64 and 4.65) needs to be

verified. The 140x60 mm hole 300 mm from the support edge fulfils the requirements in LVL 36 C joist.

9. CALCULATION EXAMPLES OF LVL STRUCTURES

d,(x=323mm)

= 0,4 m ∙ 4,03 kNm

2

∙ �1 − 0,3 m + 0,045 m/2

4,5 m � = 3,13 kN

d,(x=323mm)

= 0,4 m ∙ 4,03 kNm

2

∙ (0,3 m + 0,045 m/2)

2

∙ �4,5 m − �0,3 m + 0,045 m 2 ��

d,(x=323mm)

= 1,1 kNm

t,90,d

= 3,13 kN ∙ 0,06 m 4 ∙ 0,24 m ∙ �3 − � 0,06 m 0,24m �

2

� + 0,008 ∙ 1,1 kNm 0,09 m = 0,57 kN + 0,10 kN = 0,67 kN

t,90,d

=

t,90,d

0,5∙

t,90

∙ ∙

t,90

=

0,67 kN

0,5∙0,15 m∙0,045 m∙1,0

= 0,20

Nmm

2

t,90,d

→ OK

d

=

τ

1,5∙

d

∙(ℎ−ℎ

d

)

v,d

(4.62)

τ

= 1,85 ∙ �1 +

� ∙ �

d

0,2

= 1,85 ∙ �1 +

0,14 m 0,24 m

� ∙ �

0,06 m 0,24 m

0,2

= 2,22

(4.63)

d

=

τ

∙ 1,5 ∙

d

∙ (ℎ − ℎ

d

) = 2,22 ∙

1,5 ∙ 3,13 kN

45 mm ∙ (240 mm − 60 mm) = 1,3 Nmm

2

v,0,edge,d

=

mod M

v,0,edge,k

= 0,8 1,2 ∙ 4,5 Nmm

2

= 3,0 N/mm

2

d

v,0,edge,d

→ OK

d n

+

o,d o m,d

≤ 1

and

d n

+

u,d u m,d

≤ 1

(4.64 and 4.65)

n

=

∙�ℎ

2

−ℎ

d2

� 6

=

45 mm∙�(240 mm)

2

−(60 mm)

2

6

= 4,05 ∙ 10

5

mm

3

(4.66)

o,d

=

o u

+

o

d

2

=

∙ℎ

ro

∙ℎ

ro

+ ∙ℎ

ru

d

2

(4.67)

o,d

45 mm ∙ 90 mm

45 mm ∙ 90 mm + 45 mm ∙ 90 mm ∙ 3,13 kN ∙ 140 mm 2 = 0,11 kNm

o

=

∙ℎ

ro2

6

=

45 mm∙(90 mm)

2

6

= 60750 mm

3

(4.69)

m,0,d

=

mod M

h

m,0,k

= 0,8 1,2 ∙ 1,03 ∙ 32 Nmm

2

= 22,1 N/mm

2

d n

+

o,d o m,d

= 1,1 kNm 4,05 ∙ 10

5

mm

3

+ 0,11 kNm 60750 mm

3

22,1N/mm

2

= 4,5N/mm

2

22,1N/mm

2

= 0,20 ≤ 1 → OK

d,(x=323mm)

= 0,4 m ∙ 4,03 kNm

2

∙ �1 − 0,3 m + 0,045 m/2

4,5 m � = 3,13 kN

d,(x=323mm)

= 0,4 m ∙ 4,03 kNm

2

∙ (0,3 m + 0,045 m/2)

2

∙ �4,5 m − �0,3 m + 0,045 m 2 ��

d,(x=323mm)

= 1,1 kNm

t,90,d

= 3,13 kN ∙ 0,06 m 4 ∙ 0,24 m ∙ �3 − � 0,06 m 0,24m �

2

� + 0,008 ∙ 1,1 kNm 0,09 m = 0,57 kN + 0,10 kN = 0,67 kN

t,90,d

=

t,90,d

0,5∙

t,90

∙ ∙

t,90

=

0,67 kN

0,5∙0,15 m∙0,045 m∙1,0

= 0,20

Nmm

2

t,90,d

→ OK

d

=

τ

1,5∙

d

∙(ℎ−ℎ

d

)

v,d

(4.62)

τ

= 1,85 ∙ �1 +

� ∙ �

d

0,2

= 1,85 ∙ �1 +

0,14

0,24 m

� ∙ �

0,06

0,24 m

0,2

= 2,22

(4.63)

d

=

τ

∙ 1,5 ∙

d

∙ (ℎ − ℎ

d

) = 2,22 ∙

1,5 ∙ 3,13 kN

45 mm ∙ (240 mm − 60 mm) = 1,3 Nmm

2

v,0,edge,d

=

mod M

v,0,edge,k

= 0 8 1,2 ∙ 4,5 Nmm

2

= 3,0 N/mm

2

d

v,0,edge,d

→ OK

d n

+

o,d o m,d

≤ 1

and

d n

+

u,d u m,d

≤ 1

(4.64 and 4.65)

n

=

∙�ℎ

2

−ℎ

d2

� 6

=

45 mm∙�(240 mm)

2

−(60 mm)

2

6

= 4,05 ∙ 10

5

mm

3

(4.66)

o,d

=

o u

+

o

d

2

=

∙ℎ

ro

∙ℎ

ro

+ ∙ℎ

ru

d

2

(4.67)

o,d

=

45 m ∙ 90 mm

45 mm ∙ 90 mm + 45 mm ∙ 90 mm ∙ 3,13 kN ∙ 140 mm 2 = 0,11 kNm

o

=

∙ℎ

ro2

6

=

45 mm∙(90 mm)

2

6

= 60750 mm

3

(4.69)

m,0,d

=

mod M

h

m,0,k

= 0,8 1,2 ∙ 1,03 ∙ 32 Nmm

2

= 22,1 N/mm

2

d n

+

o,d o m,d

= 1,1 kNm 4,05 ∙ 10

5

mm

3

+ ,11 kN 60750 mm

3

22,1N/mm

2

= 4,5N/mm

2

22,1N/mm

2

= 0,20 ≤ 1 → OK

,(x 323m )

, ∙ ,

2

0,3 m + 0,

/

,

,

,(x 323 )

= , ∙ ,

kN

2

∙ ( ,

,

) ∙

,

,

,

2

d,(x=323mm)

= 1,

t,90,

,

∙ ,

∙ ,

∙ �

,

,

2

� ,

∙ , ,

,

,

,

t,90,d

=

t,90,d

0,5∙

t,90

∙ ∙

t,90

0,67 k

0,5∙0,15 ∙0,045 m∙1,0

,2

mm

2

t,90,

τ

1,5∙

d

∙(ℎ ℎ

d

)

v,

(4.62)

τ

,

d

ℎ 0,2

,

0,14

0,24 m

0,06

0,24 m 0,2

,

( . )

d τ

∙ 1,5 ∙

d

∙ (

) ,

, ∙ , 3 N

45 mm ∙ (240 mm − 60 mm) = 1,3 Nm

2

v,0,e ge,

=

o

v,0,e ge,k

0,8 1,2 ∙ 4,5 N

2

,

2

v,0,e ge,

d n o,d o ,d

≤ 1

d n u,d u ,d

1

(4.64 and . )

n

=

∙�ℎ

2

d2

� 6

=

45

∙�(240

)

2

(60

)

2

6

,

5

mm

3

( . )

o,d

o u o

d

2

∙ℎ

ro

∙ℎ

ro

∙ℎ

ru

d

2

( . )

o,

∙ 9

∙ ,

m ,

o ∙ℎ

ro2

6

=

45

∙(90

)

2

6

3

( . )

,0,

mo

h

,0,k

, , ∙ ,03 ∙ 32

2

= 22,1 N/mm

2

o, o ,

,

,0 ∙

5

3

,

6

3

,

2

, N

2

,

2

,

K

d,(x=323mm)

= 0,4 m ∙ 4,03 kNm

2

∙ �1 − 0,3 m + 0,045 m/2

4,5 m � = 3,13 kN

d,(x=323mm)

0,4 m ∙ 4,03 kNm

2

∙ (0,3 m + 0,045 m/2)

2

∙ �4,5 m − �0,3 m + 0,045 m 2 ��

d,(x=323mm)

= 1,1 kN

t,90,d

= 3,13 kN ∙ 0,06 m 4 ∙ 0,24 m ∙ �3 − � ,06

0,24m �

2

� + 0,008 ∙ 1,1 kNm 0,09 m = 0,57 kN + 0,10 kN = 0,67 kN

t,90,d

=

t,90,d

0,5∙

t,90

∙ ∙

t,90

=

0,67 kN

0,5∙0,15 m∙0,045 m∙1,0

= 0,20

Nmm

2

t,90,d

→ OK

d

=

τ

1,5∙

d

∙(ℎ−ℎ

d

)

v,d

(4.62)

τ

= 1,85 ∙ �1 +

� ∙ �

d

0,2

= 1,85 ∙ �1 +

0,14

0,24 m

� ∙ �

0,06

0,24 m

0,2

= 2,22

(4.63)

d

=

τ

∙ 1,5 ∙

d

∙ (ℎ − ℎ

d

) = 2,22 ∙

1,5 ∙ 3,13 kN

45 mm ∙ (240 mm − 60 mm) = 1,3 Nmm

2

v,0,edge,d

=

mod M

v,0,edge,k

= 0,8 1,2 ∙ 4,5 Nmm

2

= 3,0 N/mm

2

d

v,0,edge,d

→ OK

d n

+

o,d o m,d

≤ 1

and

d n

+

u,d u m,d

≤ 1

(4.64 and 4.65)

n

=

∙�ℎ

2

−ℎ

d2

� 6

=

45 mm∙�(240 mm)

2

−(60 mm)

2

6

= 4,05 ∙ 10

5

mm

3

6

o,d

o u

+

o

d

2

=

∙ℎ

ro

∙ℎ

ro

+ ∙ℎ

ru

d

2

(4.67)

o,d

=

45 mm ∙ 90 mm

45 mm ∙ 90 mm + 45 mm ∙ 90 mm ∙ 3,13 kN ∙ 140 mm 2 = 0,11 kNm

o

=

∙ℎ

ro2

6

=

45 mm∙(90 mm)

2

6

= 60750 mm

3

(4.69)

m,0,d

=

od M

h

m,0,k

= 0 8 1,2 ∙ 1 03 ∙ 32 Nmm

2

= 22,1 N/mm

2

d n

+

o,d o m,d

= 1,1 kN 4,05 ∙ 10

5

mm

3

+ ,11 kN 60750 mm

3

22,1N/mm

2

= 4,5N/mm

2

22,1N/mm

2

= 0,20 ≤ 1 → OK

d,

Nm

5 m

,

=

,3 m + 0,

045 m

,

23mm)

,

,

,

,

,

,

,

,

,

,

,

,

,

,

,2

,

,

, ∙

v,

,

, 4 m , 4 m , ,

,

∙ (ℎ − ℎ )

− 60 m

, ,

,

= ∙

, ,

,

= ∙ 4,5 = 3,0 N/mm

, ,

,

→ OK

+

, o ,

n ,

,

6

6

= 4,05 ∙ 10

5

mm

3

,

+

2 ∙ℎ + ℎ

,

9

, ,

, ,

,8 ,2

m

,

,

4,0 ∙ 10

7

,1N/mm

22,1N/m

208

LVL Handbook Europe