V_(d,(x=323mm))=0,4 m∙4,03 kN/m^2 ∙(1-(0,3 m+0,045 m/2)/(4,5 m))=3,13 kN
M_(d,(x=323mm))=(0,4 m∙4,03 kN/m^2 ∙(0,3 m+0,045 m/2))/2∙(4,5 m-(0,3 m+(0,045 m)/2))
M_(d,(x=323mm))=1,1 kNm
F_(t,90,d)=(3,13 kN∙0,06 m)/(4∙0,24 m)∙[3-((0,06 m)/0,24m)^2 ]+0,008∙(1,1 kNm)/(0,09 m)=0,57 kN+0,10
kN=0,67 kN
σ_(t,90,d)=F_(t,90,d)/(0,5∙l_(t,90)∙b∙k_(t,90) )=(0,67 kN)/(0,5∙0,15 m∙0,045 m∙1,0)=0,20 N/mm^2 ≤f_
(t,90,d)→OK
The verification of shear stress concentration at the hole edge shall fulfil the condition:
τ_d=k_τ∙(1,5∙V_d)/(b∙(h-h_d ) )≤f_(v,d)
(4.62)
Where
k_τ=1,85∙(1+a/h)∙(h_d/h)^0,2=1,85∙(1+(0,14 m)/(0,24 m))∙((0,06 m)/(0,24 m)
(4.63)
τ_d=k_τ∙(1,5∙V_d)/(b∙(h-h_d ) )=2,22∙(1,5∙3,13 kN)/(45 mm∙(240 mm-60 mm) )=
f_(v,0,edge,d)=k_mod/γ_M ∙f_(v,0,edge,k)=0,8/1,2∙4,5 N/mm^2 =3,0 N/mm^2
τ_d≤f_(v,0,edge,d)→OK
Bending stress at the location of a rectangular hole is verified by the equations:
(M_d/W_n +M_(o,d)/W_o )/f_(m,d) ≤1 and (M_d/W_n +M_(u,
(4.64 and 4.65)
Where
W_n=(b∙(h^2-h_d^2 ))/6=(45 mm∙((240 mm)^2 〖-(60 mm)〗^2 ))/6=4,0
(4.66)
M_(o,d)=A_o/(A_u+A_o )∙V_d∙a/2=(b∙h_ro)/(b∙h_ro+b∙h_ru )∙V_d∙a/2
(4.67)
M_(o,d)=(45 mm∙90 mm)/(45 mm∙90 mm+45 mm∙90 mm)∙3,13 kN∙(140 mm
W_o=(b∙h_ro^2)/6=(45 mm∙(90 mm)^2)/6=60750 mm^3
(4.69)
f_(m,0,d)=k_mod/γ_M ∙k_h∙f_(m,0,k)=0,8/1,2∙1,03∙32 N/mm^2 =22,1 N/mm^2
(M_d/W_n +M_(o,d)/W_o )/f_(m,d) =((1,1 kNm)/(4,05∙〖10〗^5 mm^3 )+(0,
(22,1N/mm^2 )=(4,5N/mm^2)/(22,1N/mm^2 )=0,20≤1→OK
Since the hole is at the centre line of the cross section, only one of the equations (4.64 and 4.65) needs to be
verified. The 140x60 mm hole 300 mm from the support edge fulfils the requirements in LVL 36 C joist.
9. CALCULATION EXAMPLES OF LVL STRUCTURES
d,(x=323mm)
= 0,4 m ∙ 4,03 kNm
2
∙ �1 − 0,3 m + 0,045 m/2
4,5 m � = 3,13 kN
d,(x=323mm)
= 0,4 m ∙ 4,03 kNm
2
∙ (0,3 m + 0,045 m/2)
2
∙ �4,5 m − �0,3 m + 0,045 m 2 ��
d,(x=323mm)
= 1,1 kNm
t,90,d
= 3,13 kN ∙ 0,06 m 4 ∙ 0,24 m ∙ �3 − � 0,06 m 0,24m �
2
� + 0,008 ∙ 1,1 kNm 0,09 m = 0,57 kN + 0,10 kN = 0,67 kN
t,90,d
=
t,90,d
0,5∙
t,90
∙ ∙
t,90
=
0,67 kN
0,5∙0,15 m∙0,045 m∙1,0
= 0,20
Nmm
2
≤
t,90,d
→ OK
d
=
τ
∙
1,5∙
d
∙(ℎ−ℎ
d
)
≤
v,d
(4.62)
τ
= 1,85 ∙ �1 +
ℎ
� ∙ �
ℎ
d
ℎ
�
0,2
= 1,85 ∙ �1 +
0,14 m 0,24 m
� ∙ �
0,06 m 0,24 m
�
0,2
= 2,22
(4.63)
d
=
τ
∙ 1,5 ∙
d
∙ (ℎ − ℎ
d
) = 2,22 ∙
1,5 ∙ 3,13 kN
45 mm ∙ (240 mm − 60 mm) = 1,3 Nmm
2
v,0,edge,d
=
mod M
∙
v,0,edge,k
= 0,8 1,2 ∙ 4,5 Nmm
2
= 3,0 N/mm
2
d
≤
v,0,edge,d
→ OK
d n
+
o,d o m,d
≤ 1
and
d n
+
u,d u m,d
≤ 1
(4.64 and 4.65)
n
=
∙�ℎ
2
−ℎ
d2
� 6
=
45 mm∙�(240 mm)
2
−(60 mm)
2
�
6
= 4,05 ∙ 10
5
mm
3
(4.66)
o,d
=
o u
+
o
∙
d
∙
2
=
∙ℎ
ro
∙ℎ
ro
+ ∙ℎ
ru
∙
d
∙
2
(4.67)
o,d
45 mm ∙ 90 mm
45 mm ∙ 90 mm + 45 mm ∙ 90 mm ∙ 3,13 kN ∙ 140 mm 2 = 0,11 kNm
o
=
∙ℎ
ro2
6
=
45 mm∙(90 mm)
2
6
= 60750 mm
3
(4.69)
m,0,d
=
mod M
∙
h
∙
m,0,k
= 0,8 1,2 ∙ 1,03 ∙ 32 Nmm
2
= 22,1 N/mm
2
d n
+
o,d o m,d
= 1,1 kNm 4,05 ∙ 10
5
mm
3
+ 0,11 kNm 60750 mm
3
22,1N/mm
2
= 4,5N/mm
2
22,1N/mm
2
= 0,20 ≤ 1 → OK
d,(x=323mm)
= 0,4 m ∙ 4,03 kNm
2
∙ �1 − 0,3 m + 0,045 m/2
4,5 m � = 3,13 kN
d,(x=323mm)
= 0,4 m ∙ 4,03 kNm
2
∙ (0,3 m + 0,045 m/2)
2
∙ �4,5 m − �0,3 m + 0,045 m 2 ��
d,(x=323mm)
= 1,1 kNm
t,90,d
= 3,13 kN ∙ 0,06 m 4 ∙ 0,24 m ∙ �3 − � 0,06 m 0,24m �
2
� + 0,008 ∙ 1,1 kNm 0,09 m = 0,57 kN + 0,10 kN = 0,67 kN
t,90,d
=
t,90,d
0,5∙
t,90
∙ ∙
t,90
=
0,67 kN
0,5∙0,15 m∙0,045 m∙1,0
= 0,20
Nmm
2
≤
t,90,d
→ OK
d
=
τ
∙
1,5∙
d
∙(ℎ−ℎ
d
)
≤
v,d
(4.62)
τ
= 1,85 ∙ �1 +
ℎ
� ∙ �
ℎ
d
ℎ
�
0,2
= 1,85 ∙ �1 +
0,14
0,24 m
� ∙ �
0,06
0,24 m
�
0,2
= 2,22
(4.63)
d
=
τ
∙ 1,5 ∙
d
∙ (ℎ − ℎ
d
) = 2,22 ∙
1,5 ∙ 3,13 kN
45 mm ∙ (240 mm − 60 mm) = 1,3 Nmm
2
v,0,edge,d
=
mod M
∙
v,0,edge,k
= 0 8 1,2 ∙ 4,5 Nmm
2
= 3,0 N/mm
2
d
≤
v,0,edge,d
→ OK
d n
+
o,d o m,d
≤ 1
and
d n
+
u,d u m,d
≤ 1
(4.64 and 4.65)
n
=
∙�ℎ
2
−ℎ
d2
� 6
=
45 mm∙�(240 mm)
2
−(60 mm)
2
�
6
= 4,05 ∙ 10
5
mm
3
(4.66)
o,d
=
o u
+
o
∙
d
∙
2
=
∙ℎ
ro
∙ℎ
ro
+ ∙ℎ
ru
∙
d
∙
2
(4.67)
o,d
=
45 m ∙ 90 mm
45 mm ∙ 90 mm + 45 mm ∙ 90 mm ∙ 3,13 kN ∙ 140 mm 2 = 0,11 kNm
o
=
∙ℎ
ro2
6
=
45 mm∙(90 mm)
2
6
= 60750 mm
3
(4.69)
m,0,d
=
mod M
∙
h
∙
m,0,k
= 0,8 1,2 ∙ 1,03 ∙ 32 Nmm
2
= 22,1 N/mm
2
d n
+
o,d o m,d
= 1,1 kNm 4,05 ∙ 10
5
mm
3
+ ,11 kN 60750 mm
3
22,1N/mm
2
= 4,5N/mm
2
22,1N/mm
2
= 0,20 ≤ 1 → OK
,(x 323m )
, ∙ ,
2
∙
0,3 m + 0,
/
,
,
,(x 323 )
= , ∙ ,
kN
2
∙ ( ,
,
) ∙
,
,
,
2
d,(x=323mm)
= 1,
t,90,
,
∙ ,
∙ ,
∙ �
,
,
�
2
� ,
∙ , ,
,
,
,
t,90,d
=
t,90,d
0,5∙
t,90
∙ ∙
t,90
0,67 k
0,5∙0,15 ∙0,045 m∙1,0
,2
mm
2
t,90,
τ
∙
1,5∙
d
∙(ℎ ℎ
d
)
v,
(4.62)
τ
,
∙
ℎ
∙
ℎ
d
ℎ 0,2
,
∙
0,14
0,24 m
∙
0,06
0,24 m 0,2
,
( . )
d τ
∙ 1,5 ∙
d
∙ (
) ,
∙
, ∙ , 3 N
45 mm ∙ (240 mm − 60 mm) = 1,3 Nm
2
v,0,e ge,
=
o
∙
v,0,e ge,k
0,8 1,2 ∙ 4,5 N
2
,
2
v,0,e ge,
d n o,d o ,d
≤ 1
d n u,d u ,d
1
(4.64 and . )
n
=
∙�ℎ
2
ℎ
d2
� 6
=
45
∙�(240
)
2
(60
)
2
�
6
,
∙
5
mm
3
( . )
o,d
o u o
∙
d
∙
2
∙ℎ
ro
∙ℎ
ro
∙ℎ
ru
∙
d
∙
2
( . )
o,
∙
∙ 9
∙
∙ ,
∙
m ,
o ∙ℎ
ro2
6
=
45
∙(90
)
2
6
3
( . )
,0,
mo
∙
h
∙
,0,k
, , ∙ ,03 ∙ 32
2
= 22,1 N/mm
2
o, o ,
,
,0 ∙
5
3
,
6
3
,
2
, N
2
,
2
,
K
d,(x=323mm)
= 0,4 m ∙ 4,03 kNm
2
∙ �1 − 0,3 m + 0,045 m/2
4,5 m � = 3,13 kN
d,(x=323mm)
0,4 m ∙ 4,03 kNm
2
∙ (0,3 m + 0,045 m/2)
2
∙ �4,5 m − �0,3 m + 0,045 m 2 ��
d,(x=323mm)
= 1,1 kN
t,90,d
= 3,13 kN ∙ 0,06 m 4 ∙ 0,24 m ∙ �3 − � ,06
0,24m �
2
� + 0,008 ∙ 1,1 kNm 0,09 m = 0,57 kN + 0,10 kN = 0,67 kN
t,90,d
=
t,90,d
0,5∙
t,90
∙ ∙
t,90
=
0,67 kN
0,5∙0,15 m∙0,045 m∙1,0
= 0,20
Nmm
2
≤
t,90,d
→ OK
d
=
τ
∙
1,5∙
d
∙(ℎ−ℎ
d
)
≤
v,d
(4.62)
τ
= 1,85 ∙ �1 +
ℎ
� ∙ �
ℎ
d
ℎ
�
0,2
= 1,85 ∙ �1 +
0,14
0,24 m
� ∙ �
0,06
0,24 m
�
0,2
= 2,22
(4.63)
d
=
τ
∙ 1,5 ∙
d
∙ (ℎ − ℎ
d
) = 2,22 ∙
1,5 ∙ 3,13 kN
45 mm ∙ (240 mm − 60 mm) = 1,3 Nmm
2
v,0,edge,d
=
mod M
∙
v,0,edge,k
= 0,8 1,2 ∙ 4,5 Nmm
2
= 3,0 N/mm
2
d
≤
v,0,edge,d
→ OK
d n
+
o,d o m,d
≤ 1
and
d n
+
u,d u m,d
≤ 1
(4.64 and 4.65)
n
=
∙�ℎ
2
−ℎ
d2
� 6
=
45 mm∙�(240 mm)
2
−(60 mm)
2
�
6
= 4,05 ∙ 10
5
mm
3
6
o,d
o u
+
o
∙
d
∙
2
=
∙ℎ
ro
∙ℎ
ro
+ ∙ℎ
ru
∙
d
∙
2
(4.67)
o,d
=
45 mm ∙ 90 mm
45 mm ∙ 90 mm + 45 mm ∙ 90 mm ∙ 3,13 kN ∙ 140 mm 2 = 0,11 kNm
o
=
∙ℎ
ro2
6
=
45 mm∙(90 mm)
2
6
= 60750 mm
3
(4.69)
m,0,d
=
od M
∙
h
∙
m,0,k
= 0 8 1,2 ∙ 1 03 ∙ 32 Nmm
2
= 22,1 N/mm
2
d n
+
o,d o m,d
= 1,1 kN 4,05 ∙ 10
5
mm
3
+ ,11 kN 60750 mm
3
22,1N/mm
2
= 4,5N/mm
2
22,1N/mm
2
= 0,20 ≤ 1 → OK
d,
Nm
5 m
,
=
,3 m + 0,
045 m
,
23mm)
,
,
,
,
,
,
,
,
,
,
,
,
,
,
,2
,
,
, ∙
v,
,
, 4 m , 4 m , ,
,
∙ (ℎ − ℎ )
− 60 m
, ,
,
= ∙
, ,
,
= ∙ 4,5 = 3,0 N/mm
≤
, ,
,
→ OK
+
, o ,
n ,
,
6
6
= 4,05 ∙ 10
5
mm
3
,
+
2 ∙ℎ + ℎ
,
9
, ,
, ,
,8 ,2
m
,
,
4,0 ∙ 10
7
,1N/mm
22,1N/m
208
LVL Handbook Europe




